(2x-7)^2-3(2x-7)-88=2(x-9)(2x+1)

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Solution for (2x-7)^2-3(2x-7)-88=2(x-9)(2x+1) equation: 



(2x-7)^2-3(2x-7)-88=2(x-9)(2x+1)

We move all terms to the left:

(2x-7)^2-3(2x-7)-88-(2(x-9)(2x+1))=0

We multiply parentheses

(2x-7)^2-6x-(2(x-9)(2x+1))+21-88=0

We multiply parentheses ..

-(2(+2x^2+x-18x-9))+(2x-7)^2-6x+21-88=0



We calculate terms in parentheses: -(2(+2x^2+x-18x-9)), so:

2(+2x^2+x-18x-9)

We multiply parentheses

4x^2+2x-36x-18

We add all the numbers together, and all the variables

4x^2-34x-18

Back to the equation:

-(4x^2-34x-18)



We add all the numbers together, and all the variables

-6x-(4x^2-34x-18)+(2x-7)^2-67=0

We get rid of parentheses

-4x^2-6x+34x+(2x-7)^2+18-67=0

We add all the numbers together, and all the variables

-4x^2+28x+(2x-7)^2-49=0

We move all terms containing x to the left, all other terms to the right

-4x^2+28x+(2x-7)^2=49

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